Yes, great question. The FBD of the bolt will have the “mg” pointed down (weight of the bolt) and a normal force pointed up (force from ocean). There is no “a” in the “ma” part of F = ma since it is in freefall and is no longer accelerating.
In problem 6 of the “Newton’s Laws” worksheet, the problem asks to find the force exerted upon a .22 kg bolt by ocean water as it falls at a terminal velocity of 43 m/s. My force pair would be the ocean interacting with the bolt. What would my free body diagram be for each of the two forces? Is there a certain part of this video that would help solve this problem?
Yes, great question. The FBD of the bolt will have the “mg” pointed down (weight of the bolt) and a normal force pointed up (force from ocean). There is no “a” in the “ma” part of F = ma since it is in freefall and is no longer accelerating.
In problem 6 of the “Newton’s Laws” worksheet, the problem asks to find the force exerted upon a .22 kg bolt by ocean water as it falls at a terminal velocity of 43 m/s. My force pair would be the ocean interacting with the bolt. What would my free body diagram be for each of the two forces? Is there a certain part of this video that would help solve this problem?